skydivellama 0 #26 May 30, 2007 I'll throw in one that starts from the southern hemisphere. I'd be smack in the middle of Spain! Just outside of someplace called San Martin de Valdeiglesias, west of Madrid. Cool! "Perhaps she saw before her a lifetime of walking on the ruined earth and chose instead a single moment in the air." -Carolyn Parkhurst Quote Share this post Link to post Share on other sites
kallend 1,683 #27 May 30, 2007 QuoteQuote And, for physics geeks, how long would it take you to get there? Since the original question ignores air resistance (or you'd never make it all the way through to the other side) you may ignore air resistance in this part too. 42 :-) seconds? leap years?... The only sure way to survive a canopy collision is not to have one. Quote Share this post Link to post Share on other sites
kallend 1,683 #28 May 30, 2007 QuoteFor the purposes of the problem, should we also assume that the Earth is a true sphere? Then the volumetric radius is 6371 km. thus the distance is 12742 km What about gravity? g is 9.8 ish at the surface of the earth but as you move towards the centre, what happens?.. g = GM/(r^2) so as radius gets smaller g gets bigger so when r = 0 g is given by a divide by zero error!! bollox, my simple head hurts. Newton's shell theorem takes care of that.... The only sure way to survive a canopy collision is not to have one. Quote Share this post Link to post Share on other sites
woodpecker 0 #29 May 30, 2007 11 days errr.......42 minutesSONIC WOODY #146 There is a fine line between cockiness and confidence -- which side of the line are you on? Quote Share this post Link to post Share on other sites
shropshire 0 #30 May 30, 2007 So, For a solid sphere this means that for any particle, the only gravitational force it feels will be due to the matter closer to center of the sphere .....thus as r (the distance to go to the centre of the Earth) tends to 0 the mass below it will also tend to 0. Quote The traveler accelerates toward the center of the Earth and is momentarily weightless when passing through the geometric center at about 7900 m/s or almost 17,700 miles/hr. The traveler would pop up on the opposite side of the Earth after a little more than 42 minutes. But unless he or she grabs something to hold on, they will fall back for a return journey and continue to oscillate with a round-trip time of 84.5 minutes. (.)Y(.) Chivalry is not dead; it only sleeps for want of work to do. - Jerome K Jerome Quote Share this post Link to post Share on other sites
kingbunky 3 #31 May 30, 2007 Quote after a little more than 42 minutes. so, the answer actually is 42? "Hang on a sec, the young'uns are throwin' beer cans at a golf cart." MB4252 TDS699 killing threads since 2001 Quote Share this post Link to post Share on other sites
jakee 1,280 #32 May 30, 2007 Quote Quote after a little more than 42 minutes. so, the answer actually is 42? Awesome.Do you want to have an ideagasm? Quote Share this post Link to post Share on other sites
woodpecker 0 #33 May 30, 2007 Thats what I said! Tony.......your a geek!SONIC WOODY #146 There is a fine line between cockiness and confidence -- which side of the line are you on? Quote Share this post Link to post Share on other sites
shropshire 0 #34 May 30, 2007 and?.... your point is? (.)Y(.) Chivalry is not dead; it only sleeps for want of work to do. - Jerome K Jerome Quote Share this post Link to post Share on other sites
kallend 1,683 #35 May 30, 2007 Quote 11 days errr.......42 minutes Isn't physics wonderful?... The only sure way to survive a canopy collision is not to have one. Quote Share this post Link to post Share on other sites
kallend 1,683 #36 May 30, 2007 QuoteSo, For a solid sphere this means that for any particle, the only gravitational force it feels will be due to the matter closer to center of the sphere .....thus as r (the distance to go to the centre of the Earth) tends to 0 the mass below it will also tend to 0. Quote The traveler accelerates toward the center of the Earth and is momentarily weightless when passing through the geometric center at about 7900 m/s or almost 17,700 miles/hr. The traveler would pop up on the opposite side of the Earth after a little more than 42 minutes. But unless he or she grabs something to hold on, they will fall back for a return journey and continue to oscillate with a round-trip time of 84.5 minutes. The oscillation period is exactly the same as the orbital period of a satellite in a circular orbit at the same distance from the center (ignoring air resistance, of course). So if the satellite passes overhead as you jump down the hole, it will pass over as you emerge on the other side of the planet.... The only sure way to survive a canopy collision is not to have one. Quote Share this post Link to post Share on other sites
shropshire 0 #37 May 30, 2007 I saw that too, on the site that I ripped off the answer from.. not so intuative.... got to love physics. (.)Y(.) Chivalry is not dead; it only sleeps for want of work to do. - Jerome K Jerome Quote Share this post Link to post Share on other sites
Grips 0 #38 May 30, 2007 Quote If i fell through I'd be about 50km off the East coast of Bermuda, hmmmmm wonder if that is inside the triangle Yep, me too. Hmmm...maybe all the people that disappear in the Bermuda Triangle end up in Perth? Quote Share this post Link to post Share on other sites
skydave238 0 #39 May 30, 2007 I'd end up just of the coast of hawaii! Aloha! Ready...Set...Go..! SkydiveSwakop Quote Share this post Link to post Share on other sites
Viking 0 #40 May 30, 2007 i would end up 886 miles North West of Ile Amsterdam part of the French Antarctic Lands.I swear you must have footprints on the back of your helmet - chicagoskydiver My God has a bigger dick than your god -George Carlin Quote Share this post Link to post Share on other sites
Nightingale 0 #41 May 30, 2007 I'd be slightly off the coast of Madagascar. Quote Share this post Link to post Share on other sites
billvon 2,478 #42 May 30, 2007 >The traveler would pop up on the opposite side of the Earth after a little >more than 42 minutes. That's true if the hole is drilled straight through the center of the earth. But what if it's drilled on a tangent, and you slide down the (frictionless) walls and slide up the other side? The suprising result is that it ALWAYS 42 minutes. Which means that if you drill a tunnel from LA to NY, put a train in it with frictionless wheels, and pump all the air out, you could get from LA to NY in 42 minutes with zero energy expended. Actually any two places on the planet could be linked by such a tunnel - it would always take 42 minutes. Quote Share this post Link to post Share on other sites
Clownburner 0 #43 May 30, 2007 Assume all ropes are inelastic, all pulleys are frictionless, and all cows are perfectly spherical.7CP#1 | BTR#2 | Payaso en fuego Rodriguez "I want hot chicks in my boobies!"- McBeth Quote Share this post Link to post Share on other sites
kallend 1,683 #44 May 30, 2007 Quote>The traveler would pop up on the opposite side of the Earth after a little >more than 42 minutes. That's true if the hole is drilled straight through the center of the earth. But what if it's drilled on a tangent, and you slide down the (frictionless) walls and slide up the other side? The suprising result is that it ALWAYS 42 minutes. Which means that if you drill a tunnel from LA to NY, put a train in it with frictionless wheels, and pump all the air out, you could get from LA to NY in 42 minutes with zero energy expended. Actually any two places on the planet could be linked by such a tunnel - it would always take 42 minutes. Which, of course, is why my commute takes 42 minutes each way unless I have to stop for a Satanic traffic light.... The only sure way to survive a canopy collision is not to have one. Quote Share this post Link to post Share on other sites
