SarahC07 0 #1 March 30, 2004 yeah, so i have a hw assigment for my business calc class due in an hour... HELP! Well.. here is a start... y = (x) / (x-3)^2 Find the second derivative of the above equation .. Sarah Quote Share this post Link to post Share on other sites
colintri 0 #2 March 30, 2004 It's easy. If you know the quotient rule, just follow it. Quote Share this post Link to post Share on other sites
beowulf 1 #3 March 30, 2004 hmph just wait to you start doing integration. I would help but its been a few years since I last did any calculus and have never needed it. I could remember how to do even the simplest derivative with out having to break out my old text book first. Quote Share this post Link to post Share on other sites
SarahC07 0 #4 March 30, 2004 Oh sorry my mistake.. it want's the second derivate... did I say that? I can get the first one... but the 2nd is CRAZY! Quote Share this post Link to post Share on other sites
kallend 1,672 #5 March 30, 2004 Quoteyeah, so i have a hw assigment for my business calc class due in an hour... HELP! Well.. here is a start... y = (x) / (x-3)^2 Find the second derivative of the above equation .. Sarah It's a standard type of problem. I bet you $10 it's in your text book.... The only sure way to survive a canopy collision is not to have one. Quote Share this post Link to post Share on other sites
SarahC07 0 #6 March 30, 2004 Okay that one is reasonably easy.. I could probably make something up for that... don't know if it will be right but... HERE try this one... And my prof doesn't teach out of the book... i really wish he did Use the given 2nd derivative and the domain of f(x) to determine the intervals where the function f(x) is concave up and where it is concave down. Domain of f(x) is All REALS f''(x)= (x^2 -36) (x+2)^2 (1-x) .... Quote Share this post Link to post Share on other sites
brits17 0 #7 March 30, 2004 what did you come up with for your first derivative that makes the 2nd one off the hook? _______________________ aerialkinetics.com Quote Share this post Link to post Share on other sites
AggieDave 6 #8 March 30, 2004 You should really call up Morgan, she's at the house, she's scary good at math and calc.--"When I die, may I be surrounded by scattered chrome and burning gasoline." Quote Share this post Link to post Share on other sites
Kat1221 0 #9 March 30, 2004 I think its too late, but anyways.... I did it really quickly, so check for simple calculation errors. And you can simplify it by multiplying a lot of stuff out: (4(x+3)(x+3)^8 + ((x+3)^2 + x(2(X+3))(8(x+3)^7)) / (X+3)^8 And yeah - just wait for integration! Quote Share this post Link to post Share on other sites
SarahC07 0 #10 March 30, 2004 y' = (x-3)^2(1) - (x)2(x-3)(1) / ((x-3)^2)^2 ? Quote Share this post Link to post Share on other sites
Kat1221 0 #11 March 30, 2004 For the second question, just find the second derivative to that equation. In the regions where the second derivative is positive, the function is concave up, and in the regions where the second derivative is negative then the funtion is concave down. Quote Share this post Link to post Share on other sites
SarahC07 0 #12 March 30, 2004 I understand the steps.. and I know how to integrate... actually easier for me LOL I'm just stressed because the answers are so freakin weird that I think I'm wrong... so maybe my answers are right... who knows... Sarah Quote Share this post Link to post Share on other sites
SarahC07 0 #13 March 30, 2004 yeah I have the 2nd der and I did that... its weird... Quote Share this post Link to post Share on other sites
bertusgeert 1 #14 March 30, 2004 Quoteyeah, so i have a hw assigment for my business calc class due in an hour... HELP! Well.. here is a start... y = (x) / (x-3)^2 Find the second derivative of the above equation .. Sarah HEY! WHAT DOES THIS HAVE TO DO WITH SKYDIVING?! Unless you are calculating something about fall rate of a birdman! --------------------------------------------- As jy dom is moet jy bloei! Quote Share this post Link to post Share on other sites
SarahC07 0 #15 March 30, 2004 yeah screw it... I'll just use the answers I get... Quote Share this post Link to post Share on other sites
Kat1221 0 #16 March 30, 2004 QuoteI understand the steps.. and I know how to integrate... actually easier for me LOL I'm just stressed because the answers are so freakin weird that I think I'm wrong... so maybe my answers are right... who knows... Sarah Oops, sorry I guess I didn't realize what you were asking. I'd have to say go with the weird answers - thats what I do! Good luck Quote Share this post Link to post Share on other sites Join the conversation You can post now and register later. If you have an account, sign in now to post with your account. Note: Your post will require moderator approval before it will be visible. Reply to this topic... × Pasted as rich text. Paste as plain text instead Only 75 emoji are allowed. × Your link has been automatically embedded. Display as a link instead × Your previous content has been restored. Clear editor × You cannot paste images directly. Upload or insert images from URL. Insert image from URL × Desktop Tablet Phone Submit Reply 0
