# Line slope calculator 4x+y=30

**Straight line given by points A[5; 10] and B[6; 6]**

## Calculation:

**Slope-intercept form of line:**y = -4x+30

**Canonical form of the line equation:**4x+y-30 = 0

**Parametric form of the line equation:**

x = t+5

y = -4t+10 ; t ∈ R

**Slope:**m = -4

**Slope angle of line: φ =**-75°57'50″ = -1.3258 rad

**X intercept:**x

_{0}= 7.5

**Y intercept:**y

_{0}= q = 30

**Distance line from the origin:**d

_{0}= 7.2761

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; -4)

**Normal vector: n =**(4; 1)

**Midpoint of the segment AB: M =**[5.5; 8]

**Perpendicular Bisector equation:**x-4y+26.5 = 0

**Vector OA = (5; 10) ; |OA| = 11.1803**

**Vector OB = (6; 6) ; |OB| = 8.4853**

**Scalar product OA .OB = 90**

**Angle ∠ AOB = 18°26'6″ = 0.3218 rad**