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dmcoco84

Math Help

By dmcoco84, in The Bonfire

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dmcoco84    5

dmcoco84
Anyone good at calculus? I need help! :S

what is the derivative of this natural log.

ln (square root sign) (2x+3)/(4x+5)

then I have to find f'(0)

If you can find the derivative I can find f'(0) easy


Edited to add: I can do the quotient rule but the square root is throwing me off.

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dmcoco84    5

dmcoco84
to find the derivative of a natural log you put take the derviative of the function over the function so the derviative of x = 1 so yes f(x) ln x = 1/x But the problem I am doing has more too it.

The SQ root over those whole function si messing me up somehwere and I can figure it out

Any math majors out there? :)

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Gone_Skiing    0

Gone_Skiing
If I read your post correctly the question is this:

f(x) = ln ( sqrt( (2x+3)/(4x+5) ) )

And you need to find f'(0).

First you can simplify a lot before actually finding the derivative.

f(x) = 1/2 ln (2x+3) - 1/2 ln(4x+5)

Also the derivative of ln(x) is 1/x dx not just 1/x.

so f'(x) = 1/(2x+3) - 2/(4x+5)

f'(0) = 1/3 - 2/5;

-Nick
--
I used to pray to God for a bicycle.
Then I realized God doesn't work that way.
So I stole one and prayed for forgiveness.

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