Math help?

[Casch 0]

Believe it or not, I'm doing this crap for fun. I'm trying to teach myself how to solve complex rational expressions. Can anyone tell me if this is simplified as much as possible?

  1      -    1

x + h         x               -h

                       =                


h                   hx^2 + xh^2

[faulknerwn 36]

Hmmm. I simplified it (if my math is right) to

hx=0

[wlie 0]

According to my TI-89 the correct answer is
1/h(x+h) - 1/hx

My other ride is the relative wind.

[Casch 0]

That would require either x or h to be zero, and neither can be zero without causing a divide by zero error in the original expression. Right? Heh, I haven't done any substancial math work since pre-calculus in high school

[deea 0]

here, I did it out for you (hope I understood correctly what you were asking for).

andreea

[faulknerwn 36]

Hmmm. Ah - I dropped a negative sign.
Let's see
1. -h^2= (1/(x+h)-1/x)(hx^2+xh^2)

2. h^2=( (x- (x+h))/(x^2+hx)) (hx^2+xh^2)

3. (-h^2)(x^2+hx) = (-h) (hx^2+xh^2)

4. -h^2x^2 -h^3x = -hx^2+xh^2

5. 0=xh^2-hx^2-h^2x-h^3x

6. (hx) (h-x-hx-h^2) = 0

Since as someone pointed out hx cannot equal 0

h=h^2+hx+x

That's as far as I get

[labrys 0]

you have an extra "h" to factor out:

-1 / x(x+h)

edit typo

Owned by Remi #?

[deea 0]

wait a sec... could you clarify your question a little bit? The other posts are confusing me :)
Are you asking if the left hand side, when simplified, results in the RHS or something simpler, or are you giving this whole thing as an equation to be solved (if so, in which variable?)
My previous post refers to option #1.

[labrys 0]

I took it the same way you did. The LHS is the complex expression and the RHS is his answer.

Owned by Remi #?

[Casch 0]

Sorry about the confusion, and thank you for your answer :) That was EXACTLY what I was looking for. Thank you so much for the help

[kallend 1,623]

Quote

According to my TI-89 the correct answer is
1/h(x+h) - 1/hx

Speaking here as a professor, I don't think the point of the exercise is to see if your TI can do it.

...

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