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`F = 8 - 2x ` <br> or `F = -2(x - 4)` <br> at equilibrium position `F = 0` <br> Hence the motion of particle is `SHM` with force constant `2` and equilibrium position `x = 4` <br> (a) Yes, motion is `SHM`. <br> (b) Equilibrium position is `x = 4` <br> (c) At `x = 6 m`, particle is at rest i.e., it is one of the extreme position Hence amlitude is `A = 2 m` and initially particle is at the extreme position. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_WFPM_PHY_XI_C04_S01_006_S01.png" width="80%"> <br> `:.` Equation of `SHM` can be written as <br> `x - 4 = 2 omegat`, where `omega = sqrt((k)/(m)) = sqrt((2)/(2)) = 1` <br> i.e., `x = 4 + 2 cos t` <br> (d) Time period, `T = (2pi)/(omega) = 2pisec`.