SansSuit 1 #1 December 21, 2011 I don't have the math skills to figure this out. I don't have the google skills to phase this in order to get an answer. I'm sure one of you all will have the knowledge. Nine playing cards, three of which are aces. They are shuffled and spread out face down. You have one attempt to pick out the 3 aces. What is the probability (or is it odds?) of this happening? Thanks!Peace, -Dawson. http://www.SansSuit.com The Society for the Advancement of Naked Skydiving Quote Share this post Link to post Share on other sites
sacex250 0 #2 December 21, 2011 First Card: 3 Aces in Nine Cards (1 in 3) Second Card: 2 Aces in Eight Cards (1 in 4) Third Card: 1 Ace in Seven Cards (1 in 7) 3 X 4 X 7 = 84 1 in 84It's all been said before, no sense repeating it here. Quote Share this post Link to post Share on other sites
ryoder 1,362 #3 December 21, 2011 QuoteQuick guess, off the top of my head: 1 in 84 First Card: 3 Aces in Nine Cards (1 in 3) Second Card: 2 Aces in Eight Cards (1 in 4) Third Card: 1 Ace in Seven Cards (1 in 7) 3*4*7=84 1 in 84 I agree."There are only three things of value: younger women, faster airplanes, and bigger crocodiles" - Arthur Jones. Quote Share this post Link to post Share on other sites
muff528 3 #4 December 21, 2011 1 in 121.5 1 in 729 chance of picking 3 cards in a particular order. 6 possible combinations of aces. so 6 in 729 chances of picking 3 aces in no particular order. OOPS! right 1 in 84 same reasoning but each card can be used only once (obviously) so 7*8*9=504 and 504/6=84 Quote Share this post Link to post Share on other sites
ghost47 18 #5 December 21, 2011 Quote1 in 729 chance of picking 3 cards in a particular order. 6 possible combinations of aces. so 6 in 729 chances of picking 3 aces in no particular order. Actually, 1 in 504 chance of picking 3 cards in a particular order (9 cards for first choice, 8 cards for second choice, 7 cards for third choice. 9 x 8 x 7 = 504. Or, to use the formula: 9! / (9-3)! = 9! / 6! = 9 x 8 x 7 = 504). So, 6 possible combination of aces = 6 in 504 chances of picking 3 aces in no particular order = 1 in 84 chances. Quote Share this post Link to post Share on other sites
muff528 3 #6 December 21, 2011 Yep! ...can't use the same "digit" twice in the same "3-digit" number. I realized that after looking at it again. Quote Share this post Link to post Share on other sites
SansSuit 1 #7 December 21, 2011 Thanks all.Peace, -Dawson. http://www.SansSuit.com The Society for the Advancement of Naked Skydiving Quote Share this post Link to post Share on other sites